**what force per unit area is water capable of exerting on a container when it freezes** This is a topic that many people are looking for. **savegooglewave.com** is a channel providing useful information about learning, life, digital marketing and online courses …. it will help you have an overview and solid multi-faceted knowledge . Today, ** savegooglewave.com ** would like to introduce to you **5.42 | SOLUTIONS for OpenStax™ **. Following along are instructions in the video below:

42. When water freezes its volume increases by nine point zero five percent. That is is that the change in volume per.

The initial volume is equal to nine point times. Ten to the minus two what force per unit area aka pressure is water capable of exerting on a container. When it freezes.

It is acceptable to use the bulk modulus of water in this problem. Great. So there basically i mean they told us bulk modulus right.

But just remember that whenever youre dealing with you know some type of you know liquid talking about pressures in this and that changes in volumes. You know youre gonna be using the bulk modulus formula down here on the right hand side all right so. It says that the change in pressure is equal to negative and the negative sign just implies that right as you increase pressure decrease volume the bulk modulus multiplied by the change in volume per.

The initial volume all right straightforward so when theyre asking us to find the what force per unit area. Remember pressure is equal to force per area alright. So in other words.

Theyre asking us to find the pressure. So this is a fairly straightforward problem. Its basically just plugging in alright.

So the we have to go to our table. Find the bulk modulus of water heres water heres the bulk modulus. 22.

Times 10 to the nine 22. Times. 10 to the nine.

Just remember all these values come with 10 to the nine at the top. Okay. So thats gonna be multiplied now my percent change right.

Which it worked out to be nine point oh five times ten to the minus two okay cool so all i got to do is calculate now. Right. So lets see so we get 22.

Times. 10 to the nine times nine point oh five right nine point oh five times ten to the minus two and wowzers. We get one point nine nine times 10 raised to lets see three six seven eight eight newtons right that is a tremendously large number thats like a hundred and ninety nine million million newtons okay thats a tremendously large number and oh its not newtons right.

Its really newtons per meter squared okay so thats how many newtons there are per square meter. And thats an insane amount right we can even you know we can break this down and two can even think about you know what it might be per square centimeter. And if i had to do that basically i would just take this value and divide.

It by ten thousand just like we did in the prior problem so if i were to do that it would be one point one point nine nine times 10 to the fourth now newtons per square centimeter. All right now how much does. This force actually relate to in you know kilograms over or mass well remember weight is equal to mg alright.

So one point nine nine. Times 10 to the fourth is equal to. Mass.

Times. 98 no divide out the 980. From both sides and lets see what it works out to be so one so divide that by.

10000. Let me do that first and then simply take it divided by 98. So two thousand two thousand thirty 31.

Right over so 32. Whatever two thousand thirty lets just say kilograms. I mean thats an insane amount right thats almost two tons per square centimeter lets i dont find it surprising that thatll fracture engine blocks and boulders and stuff like that all right so guys thank you so much for tuning in please remember to subscribe and that also makes make sense.

Why the roads around here so terrible in the winter. Right. Theres a lot of holes out there on the road in the winter.

Why here you go all right please remember to subscribe look forward to helping you with the next question take care. .

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